2b^2-12b+15=5

Solution for 2b^2-12b+15=5 equation:

Simplifying
2b2 + -12b + 15 = 5

Reorder the terms:
15 + -12b + 2b2 = 5

Solving
15 + -12b + 2b2 = 5

Solving for variable 'b'.

Reorder the terms:
15 + -5 + -12b + 2b2 = 5 + -5

Combine like terms: 15 + -5 = 10
10 + -12b + 2b2 = 5 + -5

Combine like terms: 5 + -5 = 0
10 + -12b + 2b2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(5 + -6b + b2) = 0

Factor a trinomial.
2((1 + -1b)(5 + -1b)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(1 + -1b)' equal to zero and attempt to solve:

Simplifying
1 + -1b = 0

Solving
1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1b = 0 + -1
-1b = 0 + -1

Combine like terms: 0 + -1 = -1
-1b = -1

Divide each side by '-1'.
b = 1

Simplifying
b = 1
Subproblem 2
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Solution
b = {1, 5}